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Amps drawn from headlights


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I believe the OEM headlights are 55 watt on high beam, which, if divided by 12 (volts) give the amps drawn per lamp, which is not much. If you upgrade to a higher wattage lamp, simply do the same thing again for each lamp's amp draw and then multiply times two for the "set".

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There's a basic electronic formula you can use:

 

P= I * V Power = Current * volts

P= watts

I = amps

V = volts

 

You can solve for any variable:

 

I=P/V

V=P/I

 

for lights, you know the voltage and the wattage.

 

for an example, a 12V, 55W lamp:

 

A=55/12 ~ 4.5Amps

 

ifyou had a 30AMP light,

P=30 * 12 = 360 watts.

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Guest greimann
so amps is equal to watts divided by current?

 

.....

-Ed

 

No. Amps and current are the same thing. amps = watts / voltage.

 

The actual formula is P= I V , and algebraic variations thereof.

where:

P = Watts

I = current (amps)

V = Voltage

 

If the cooling fan in question is rated in watts, then divide watts by 12 to get amps.

 

See this link for more info on DC power: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elepow.html#c1

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