ihatejoefitz Posted May 29, 2005 Share Posted May 29, 2005 In the picture where does the black and white wire from distributor go? what does v(v(12v)) and v(5v) mean? do i just put an inline resistor here? Quote Link to comment Share on other sites More sharing options...
Tony D Posted May 29, 2005 Share Posted May 29, 2005 12V is where it goes. I used the injector power source on my relay box as the source for the 12V power. The Vref source on the relay box is also a good point for the 5V source for the sensor. Using the relay box, I was able to use the resistor leads for the pullup resistors from the aforementioned voltage sources without any problems at all. Basically what you do is connect the B/W wire to the 12V source, and from that same 12V source, you attach the pullup resistor, and connect it to the TACH terminal, as well as connecting the G/B wire to the same TACH terminal. Mine used the first lug on the injector source power terminal block, B/W wire to the distributor and one leg of the 1000ohm resistor attached there, the other leg of the 1000ohm pullup resistor and the G/B wire attached to the TACH terminal on the relay board green terminal strip. The resistor was juuuuuust long enough. Were I to do it again, I would solder conventional wire to the ends of a resistor ,and then stick the WIRE into the terminal lugs, as the little resistor lead tended to fall out until I folded it over to give the terminal something to bite onto. Similarly, you have a 5V Vref terminal on the relay box green terminal strip and that 1000 ohm resistor makes a nice jumper from there over to the FIDLE pin on the same terminal strip. I may have photos of that on the cardomain site. That FIDLE terminal also gets a wire that goes to the "G" terminal on the HEI module. Hope you followed that! Quote Link to comment Share on other sites More sharing options...
ihatejoefitz Posted May 29, 2005 Author Share Posted May 29, 2005 thanks Quote Link to comment Share on other sites More sharing options...
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