josh817 Posted May 5, 2012 Share Posted May 5, 2012 Need to find the voltage as shown. I had a previous problem, the typical resistor cube where it was pulling from opposite corners. I found that to be pretty stinkin easy but this guy... I can't find a combination that works. Anyone have any clues? My logic with opposite corners was that the current splits into 3 legs, then those split into another 2, then they come back to three. so that made it [(1/3)+(1/6)+(1/3)]R Thanks guys Quote Link to comment Share on other sites More sharing options...
Six_Shooter Posted May 6, 2012 Share Posted May 6, 2012 Oh man, Kirchoff's voltage law.... It's been about 12 years since I actually used that. Quote Link to comment Share on other sites More sharing options...
josh817 Posted May 6, 2012 Author Share Posted May 6, 2012 I rather like my thinking where I say ok, current splits into three, then those two legs split into two, blah blah. I can't figure this out and its getting so frustrating I think I just may go to Radio shack, spend a dollar, and get some resistors. lol Quote Link to comment Share on other sites More sharing options...
Six_Shooter Posted May 6, 2012 Share Posted May 6, 2012 Look up Kirchoff's Voltage law, you can calculate the end result using it. Quote Link to comment Share on other sites More sharing options...
loy Posted May 6, 2012 Share Posted May 6, 2012 Or you can load up your favorite spice program and plug it in. Quote Link to comment Share on other sites More sharing options...
loy Posted May 6, 2012 Share Posted May 6, 2012 Just a quick diagram. Quote Link to comment Share on other sites More sharing options...
josh817 Posted May 6, 2012 Author Share Posted May 6, 2012 (edited) Just a quick diagram. Well, I tried 290 and 280 just for grins and neither worked. Worse though, I'm not seeing how it's just 1/3 the current (which I guess is good since that was incorrect). Oh and that's my main problem. If I knew how to draw it out correctly, I could solve without spice program. I just don't know how to draw... Edited May 6, 2012 by josh817 Quote Link to comment Share on other sites More sharing options...
Moltar Posted May 6, 2012 Share Posted May 6, 2012 (edited) What's your email address? I can scan you how I've solved it. Edited May 6, 2012 by Moltar Quote Link to comment Share on other sites More sharing options...
loy Posted May 6, 2012 Share Posted May 6, 2012 (edited) The spice program says 490V. Edited May 7, 2012 by loy Quote Link to comment Share on other sites More sharing options...
josh817 Posted May 7, 2012 Author Share Posted May 7, 2012 Thanks loy. Moltar you can just PM here, that'll work fine. I downloaded 5spice but couldn't figure out how to work it. I have 8 or 9 other bonus problems that I can't figure out but meh... I don't think I will worry about them I suppose. Quote Link to comment Share on other sites More sharing options...
Leon Posted May 7, 2012 Share Posted May 7, 2012 Yep, use KVL loop equations. You'll end up with 6 equations and 6 unknowns. You may be able to parse that down to 3 eq, 3 unk. Matrices would make quick work of the math. Quote Link to comment Share on other sites More sharing options...
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